David (Kronos Prime) Fuller
2018-02-01 13:29:43 UTC
The Big Electron ........
1 / ((((G / (c^2)) / Planck length) * 1.50122E+23) / 2pi) = 9.10936808e-31 kilograms
(1 / ((((G / (c^2)) / Planck length) / 1.38064852e-23) / (2 * pi))) / ((6.52485 * (8^0.5))^0.25) = 9.10933855e-31 kilograms
Just do it the easy way.
The pressure energy in an incompressible fluid volume, like a pressurized tank with water, can be expressed as
E = dp / ρ
where
E = energy (J/kg)
dp = pressure difference (Pa, N/m2)
ρ = density (kg/m3)
Example - Pressure Energy in a Water Tank
The pressure on a water tank is 10 bar (10^6 Pa). With density of water 1000 kg/m3 the pressure energy can be calculated as
E = (10^6 Pa) / (1000 kg/m3) = 1000 J/kg
(((c^7) / (hbar * (G^2))) / ((c^5) / (hbar * (G^2)))) / (joules / kg) = 8.98755179e+16
(6.67408e-11/2 pascals/(3.71295774e-28 kg /m^3)) = 299792458^2 joules/kg
From Vacuum Permittivity & permeability
ρv 1.0150096E+04 kg/m^3 Vacuum density
Pv 9.1224509E+20 Pa Vacuum pressure
9.1224509E+20 Pa / (1.0150096E+04 kg/m^3) = 299792458^2 joules/kg
(1.50122E+23 / (((6.52485 ((kg m) / s)) / c) / (1 * electron mass))) / (2PI) = 1
(((1.50122E+23^4) * 1.0150096E+04 (kg / (m^3))) / (c^5)) * hbar * (G^2) = 1
https://drive.google.com/file/d/1KrN4t4j1517r60RDSXl_QO1bsH3-8KgX/view?usp=sharing
1 electron mass*G/c^2/ Planck length * 1.50122E+23 /(2pi) = 1
(((1.50122E+23^4) * (1.38064852e-23^4)) / 6.52485) / (8^0.5) = 0.9999870315
1 / ((((G / (c^2)) / Planck length) * 1.50122E+23) / 2pi) = 9.10936808e-31 kilograms
(1 / ((((G / (c^2)) / Planck length) / 1.38064852e-23) / (2 * pi))) / ((6.52485 * (8^0.5))^0.25) = 9.10933855e-31 kilograms
Just do it the easy way.
The pressure energy in an incompressible fluid volume, like a pressurized tank with water, can be expressed as
E = dp / ρ
where
E = energy (J/kg)
dp = pressure difference (Pa, N/m2)
ρ = density (kg/m3)
Example - Pressure Energy in a Water Tank
The pressure on a water tank is 10 bar (10^6 Pa). With density of water 1000 kg/m3 the pressure energy can be calculated as
E = (10^6 Pa) / (1000 kg/m3) = 1000 J/kg
(((c^7) / (hbar * (G^2))) / ((c^5) / (hbar * (G^2)))) / (joules / kg) = 8.98755179e+16
(6.67408e-11/2 pascals/(3.71295774e-28 kg /m^3)) = 299792458^2 joules/kg
From Vacuum Permittivity & permeability
ρv 1.0150096E+04 kg/m^3 Vacuum density
Pv 9.1224509E+20 Pa Vacuum pressure
9.1224509E+20 Pa / (1.0150096E+04 kg/m^3) = 299792458^2 joules/kg
(1.50122E+23 / (((6.52485 ((kg m) / s)) / c) / (1 * electron mass))) / (2PI) = 1
(((1.50122E+23^4) * 1.0150096E+04 (kg / (m^3))) / (c^5)) * hbar * (G^2) = 1
https://drive.google.com/file/d/1KrN4t4j1517r60RDSXl_QO1bsH3-8KgX/view?usp=sharing
1 electron mass*G/c^2/ Planck length * 1.50122E+23 /(2pi) = 1
(((1.50122E+23^4) * (1.38064852e-23^4)) / 6.52485) / (8^0.5) = 0.9999870315