Unless they are not algebraically independent, e and pi,
then the form as follows
e/pi
Is the same as (for basic arithmetic purposes):
X/Y
In the rational functions Q(X,Y). See also
here, its very easy:
Tag 030D: 9.26. Transcendence
http://stacks.math.columbia.edu/tag/030D
Example 9.26.6. Consider the field extension Q(e,π)
formed by adjoining the numbers e and π. This field
extension has transcendence degree at least 1 since
both e and π are transcendental over the rationals.
However, this field extension might have transcendence
degree 2 if e and π are algebraically independent.
Whether or not this is true is unknown and whence
the problem of determining trdeg(Q(e,π)) is open.
The polynomials Q[X,Y], are just bivariate polynomials
with coefficients of Q and variables X,Y. The Q(X,Y)
is the field of fractions of Q[X,Y].
https://en.wikipedia.org/wiki/Field_of_fractions
To do more than basic arithmetic, you need F or C,
then Q(e,pi) is not enough. But +, -, *, / are
defined in a field of fractions,
What you need is a multivariate kind of division
and a multivariate GCD, which is a little tricky,
but Q[X,Y] is a GCD domain.
https://en.wikipedia.org/wiki/GCD_domain
I have implemented Q(X1,..,Xn) in Prolog, you
can play with it. Computing with E and PI, only
basic arithmetic, is very easy:
Jekejeke Prolog 2, Runtime Library 1.2.3
(c) 1985-2017, XLOG Technologies GmbH, Switzerland
?- use_module(library(groebner/generic)).
% 22 consults and 0 unloads in 938 ms.
Yes
?- X is (E^2-PI^2)/(E-PI).
X is E+PI
You can make a sanity check via approximations,
and using your pocket calculator (rounded and
with the usual float IEEE errors):
e^2-pi^2 = -2.4805483021587085
e-pi = -0.423310825130748
(e^2-pi^2)/(e-pi) = 5.859874482048839
e+pi = 5.859874482048838
Note this method (the result X is E+PI) of basic
arithemtic via polynomial factions works in finite
steps. You don't need infinity.
Can you refute that it works?
Post by bassam king karzeddinPost by bassam king karzeddinBig Hint: remove both decimals notations from (e & pi) to estimate (e/pi) to avoid any confusions
Have more fun with the new resultant number for sure
Regards
Bassam King Karzeddin
May 25, 2017
So, what exactly is this genius mathematicians? wonder!
e/Pi = (2718281828...)/(3141592654...)
Forget about your APPROXIMATIONS, (we know it for sure)
Can't you think properly?
Or had you got addicted to fictions? wonder!
But I know that fictions are so sweet, but reality is much sweeter for sure
So, get out of your tiny hole and say a word of truth, now
Do something useful professional mathematicians for the societies that feed you, it is still not too late
But never feel shameful if you are so professional in mathematics since there is a lot that you had missed in the last few thousands of years, for sure
Regards
Bassam King Karzeddin
07/20/2017