alternative and interesting method to generate the Six stats

[uglyvan]

roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
example:
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3

2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;

Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre

the DnD score is 3 times the stat Rank


Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6

repeat the process for each of your basic stats

just a note here:

for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

[Spalls Hurgenson]

On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6
repeat the process for each of your basic stats
for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.

Still don't see the point; it seems unduly complicated for no good
purpose (and limits you to only a fixed number of attribute points;
nobody is going to get an attribute of 13 using this system, for
instance).

But at least it isn't just random digital gibberish.

Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.

Nice day for it.

Some Random Digital Gibberish
2 ----- 7
1 ----- 8
28 ----- 1
82 ----- 84
5 ----- 90
4 ----- 52
35 ----- 3
60 ----- 28
74 ----- 71
3 ----- 5

[uglyvan]

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6
repeat the process for each of your basic stats
for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.
Still don't see the point; it seems unduly complicated for no good
purpose (and limits you to only a fixed number of attribute points;
nobody is going to get an attribute of 13 using this system, for
instance).
But at least it isn't just random digital gibberish.
Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.
Nice day for it.

feel free to add stuff from yours' so that it becomes collegial work instead of individual as from is present.

[Rick Pikul/Chakat Firepaw]

Post by uglyvan

Post by Spalls Hurgenson
Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.
Nice day for it.

feel free to add stuff from yours' so that it becomes collegial work
instead of individual as from is present.

The problem is that what you are posting amounts to scratch notes on the
details without any real insight into the underlying system concepts. It
all probably makes perfect sense to you but to the rest of us almost
everything you have posted is meaningless gibberish.

How about taking a few steps back and posting an overview of how you
intend this system to work? Don't worry about exact numbers, just the
gist.


Oh, and stop creating a new thread for every little idea you have. When
doing this kind of development work is perfectly fine to reply to
yourself. At least come up with a name and use it as a subject tag.

[uglyvan]

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6
repeat the process for each of your basic stats
for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.
Still don't see the point; it seems unduly complicated for no good
purpose (and limits you to only a fixed number of attribute points;
nobody is going to get an attribute of 13 using this system, for
instance).
But at least it isn't just random digital gibberish.
Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.
Nice day for it.

for example, if one good mathematics user would print the probabilities for ranks of 2 to 7

like in 2d6 bring 6 possibilities out of 36 combos
unfortunately I quit school one year before Baccalauréat, so I didn't learn probabilities along with integrals

:)

[Justisaur]

Post by uglyvan

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6
repeat the process for each of your basic stats
for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.
Still don't see the point; it seems unduly complicated for no good
purpose (and limits you to only a fixed number of attribute points;
nobody is going to get an attribute of 13 using this system, for
instance).
But at least it isn't just random digital gibberish.
Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.
Nice day for it.

for example, if one good mathematics user would print the probabilities for ranks of 2 to 7
like in 2d6 bring 6 possibilities out of 36 combos
unfortunately I quit school one year before Baccalauréat, so I didn't learn probabilities along with integrals
:)

On 2d6 there's always a 1 in 6 chance of both dice rolling the same
number, there's really no point in doing that, you can just roll a d6, and
stop if you roll a 1 and have the exact same chance.

So there's a 16.66% chance of stopping at 1. Since the chances of each
come out of the remaining chances overall each is 1/6 of what's left, so on
the 2nd roll it's 13.88 (16.66% of the remaining 83.33%), on the third
it's 11.67% (16.66% of the remaining 69.44%).

4 = 9.64%
5 = 8.03%
6 = 6.69%
7 = 5.58%
8 = 4.65%

etc. You get below 1% at 17, and the possibilities go to infinity.

The mean is 6 - so that's what your average human would be.

I'm not really math inclined, but I like knowing probabilities. Also I
was just figuring out this same problem 2 days ago for how long it would
take to actually find a secret door with a party in 1e.

I prefer my 27-25-23 +2 Organic method.

https://sites.google.com/site/justisaursdd/tar-pit-dugout/justisaurs27-25-23abilityscoregeneration

- Justisaur

[uglyvan]

Post by Justisaur

Post by uglyvan

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6
repeat the process for each of your basic stats
for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.
Still don't see the point; it seems unduly complicated for no good
purpose (and limits you to only a fixed number of attribute points;
nobody is going to get an attribute of 13 using this system, for
instance).
But at least it isn't just random digital gibberish.
Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.
Nice day for it.

for example, if one good mathematics user would print the probabilities for ranks of 2 to 7
like in 2d6 bring 6 possibilities out of 36 combos
unfortunately I quit school one year before Baccalauréat, so I didn't learn probabilities along with integrals
:)

On 2d6 there's always a 1 in 6 chance of both dice rolling the same
number, there's really no point in doing that, you can just roll a d6, and
stop if you roll a 1 and have the exact same chance.
So there's a 16.66% chance of stopping at 1. Since the chances of each
come out of the remaining chances overall each is 1/6 of what's left, so on
the 2nd roll it's 13.88 (16.66% of the remaining 83.33%), on the third
it's 11.67% (16.66% of the remaining 69.44%).
4 = 9.64%
5 = 8.03%
6 = 6.69%
7 = 5.58%
8 = 4.65%
etc. You get below 1% at 17, and the possibilities go to infinity.
The mean is 6 - so that's what your average human would be.
I'm not really math inclined, but I like knowing probabilities. Also I
was just figuring out this same problem 2 days ago for how long it would
take to actually find a secret door with a party in 1e.
I prefer my 27-25-23 +2 Organic method.
https://sites.google.com/site/justisaursdd/tar-pit-dugout/justisaurs27-25-23abilityscoregeneration
- Justisaur

:o I think you misunderstand the method !

there is 100% result at 7d6 roll (because there are only 6 holes in d6 rolls, and after having rolled 6d6, all gaps are filled ...

[LL]

Post by uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6

<snip>

Post by uglyvan
:o I think you misunderstand the method !
there is 100% result at 7d6 roll (because there are only 6 holes in d6 rolls, and after having rolled 6d6, all gaps are filled ...

Maybe I get it right?

prob for rank 2: 16.67% or 1 in 6
or you have rolled 2 diff. numbers
(with a probability of 83.33% or 5 in 6)
with a result of two diff. numbers. (prob. 1/3)
always take 1-p from the last, multiply w. prob
to get a matching number now:

5/6 * 1/3 = 5/18 = 27.77% for rank 3

5/6 * 2/3 * 1/2 = 10/36 = 27.77% for rank 4

10/36 * 2/3 = 10/54 = 18.51% for rank 5

10/36 * 1/3 * 5/6 = 5/18 * 5/18 = 7.71% for rank 6

25/324 * 1/6 * 1 = 1.28% for rank 7

Hopefully, I didn't screw up (sum is 99.74%, rounding error?)

% rank score
16.67 2 6
27.77 3 9
27.77 4 12
18.51 5 15
07.71 6 18
01.28 7 21

Nathty, trickthy statisticth stuff...

[tussock]

Post by LL
Maybe I get it right?

Let's see.

2nd roll, 1/6 doubles else
3rd roll, 2/6 doubles else
4th roll, 3/6 doubles else
5th roll, 4/6 doubles else
6th roll, 5/6 doubles else
7th roll, always.

2: 1/6.
3: 5/6 * 2/6.
4: 5/6 * 4/6 * 3/6.
5: 5/6 * 4/6 * 3/6 * 4/6.
6: 5/6 * 4/6 * 3/6 * 2/6 * 5/6.
7: 5/6 * 4/6 * 3/6 * 2/6 * 1/6.

Which is the same as yours, all good.

Terribly slow to roll for all six stats though. Same output as trying
to successively roll 2+, 3+, 4+, 5+, and a 6, without failure, scoring
the number you missed, and 7 if you got the lot.

[Spalls Hurgenson]

On Wed, 16 Dec 2015 04:43:51 -0800 (PST), uglyvan

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6

Wouldn't it just be easier to do (d6+1)*3?

You get exactly the same results with far less rolling.

[LL]

Post by Spalls Hurgenson
On Wed, 16 Dec 2015 04:43:51 -0800 (PST), uglyvan

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6

Wouldn't it just be easier to do (d6+1)*3?
You get exactly the same results with far less rolling.

Probabilies differ ... 18 and 21 become much more common

[Justisaur]

Post by uglyvan
:o I think you misunderstand the method !
there is 100% result at 7d6 roll (because there are only 6 holes in d6
rolls, and after having rolled 6d6, all gaps are filled ...

Yeah, that's the problem, I misunderstood the method. /sarcasm

[JimP]

On Wed, 16 Dec 2015 07:53:58 -0800 (PST), Justisaur

Post by Justisaur

Post by uglyvan
:o I think you misunderstand the method !
there is 100% result at 7d6 roll (because there are only 6 holes in d6
rolls, and after having rolled 6d6, all gaps are filled ...

Yeah, that's the problem, I misunderstood the method. /sarcasm

While this is on of the few subjects posted recently, the sarcasm
directed towards it is far more interesting than the excruciatingly
painful 'information'.

[uglyvan]

Post by Spalls Hurgenson
On Tue, 15 Dec 2015 04:56:54 -0800 (PST), uglyvan

Post by uglyvan
roll one d6;
roll a second d6;
if both d6s roll the same number then stop Rolling dice;
as long as dice rolled bring different values, keep Rolling one die;
stop Rolling dice as soon as you get two similar values;
count the number of dice rolled;
it represents your stat Rank;
1st d6: 6
2nd d6: 3
3rd d6: 4
4th d6: 3
2nd d6 = 4th d6
stop.
4 dice rolled means you have a stat Rank of Good;
Rank name
7 epic ( olympic )
6 superb
5 excellent
4 good
3 typical
2 mediocre
the DnD score is 3 times the stat Rank
Rank Score
7 ---- 21
6 ---- 18
5 ---- 15
4 ---- 12
3 ----- 9
2 ----- 6
repeat the process for each of your basic stats
for in a d6 there are only six values, if you rolled 6 dice and happend no match, then the 7th die automatically match one value.

My god, I almost understood that.
Still don't see the point; it seems unduly complicated for no good
purpose (and limits you to only a fixed number of attribute points;
nobody is going to get an attribute of 13 using this system, for
instance).
But at least it isn't just random digital gibberish.
Or is it? Perhaps I have gone mad. Yes, that's more likely it. I have
gone mad.
Nice day for it.
Some Random Digital Gibberish
2 ----- 7
1 ----- 8
28 ----- 1
82 ----- 84
5 ----- 90
4 ----- 52
35 ----- 3
60 ----- 28
74 ----- 71
3 ----- 5

in order to obtain missing values, you can do something like that :

after Rolling for the stat Rank,
roll 1d6;
results of 1,2,3 give +0
results of 4 or 5 give +1
result of 6 gives +2

:)

[uglyvan]

Rank -- Score
7 ------ 18
6 ------ 16
5 ------ 14
4 ------ 12
3 -------10
2 ------- 8

:)

[uglyvan]

sorry, I think this is bullshit...

:)

( makes me think of a Wrestler named Samson who was always smiling in spite of being stunned etc )